larkim - 51 mins ago »
On size of recording a whole multiplex; is my maths wrong here?
40Mbit/sec is the bitrate of the HD multiplex.
40/8 = 5megabytes per second of data. x 60 sec x 60 min x 24 hours = 423Gigabytes of data. So say half a terrabyte disk, or 25% of the 2Tb models. Its a lot of usage but for a fabulously useful service. It's a real shame no-one has replicated that functionality.
That seems about right but the recordings are much smaller thanks to stat muxing.
The actual hdd capacity is actually less due to the same rounding using 1000. 4236/1024 TB
4236GB is actually less than half at just over 4TB.
The available pool is allocated dynamically (variable bitrate) according to the complexity of the current content. As a result simultaneous recording of 5 HD channels will be much smaller than your calculation for the full Mux.